In an a.p if sn n 4n + 1 find the a.p
WebSolution: The sum of n terms S n = 441 Similarly, S n-1 = 356 a = 13 d= n For an AP, S n = (n/2) [2a+ (n-1)d] Putting n = n-1 in above equation, l is the last term. It is also denoted by a n. The result obtained is: S n -S n-1 = a n So, 441-356 = a n a n = 85 = 13+ (n-1)d Since d=n, n (n-1) = 72 ⇒n 2 – n – 72= 0 Solving by factorization method, WebMar 29, 2024 · Similarly find the 3rd, the 10th and the nth terms. Given Sn = 4n – n2 Taking n = 1 S1 = 4 × 1−12 = 4 – 1 = 3 ∴ Sum of first term of AP is 3 Taking n = 2 in Sn S2 = …
In an a.p if sn n 4n + 1 find the a.p
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WebJan 20, 2014 · Varun.Rawat, Meritnation Expert added an answer, on 21/1/14. We have, S n = 4n 2 + n. put n = 1, we get. S 1 = 4 (1) 2 + 1 = 4 + 1 = 5. So, First term, a 1 = 5. Put n = 2 , we … WebMar 31, 2024 · If the sum of n terms of an A.P. is 2n^2 + 5n , then its nth term is A. 4n − 3 B. 3n − 4 C. 4n + 3 D. 3n + 4 asked Jul 16, 2024 in Arithmetic Progression by Maanas ( 26.0k points) arithmetic progression
WebFeb 1, 2024 · If the sum of first n terms of an A.P is given by Sn = 3n^2 + 4n. Determine the A.P and the nth term. asked Sep 30, 2024 in Mathematics by Samantha (39.3k points) arithmetic progression; cbse; class-10; 0 votes. 1 answer. The 7th term of an AP is -1 and its 16th term is 17. The nth term of the AP is (a) (3n + 8) (b) (4n – 7) (c) (15 – 2n ...
WebWe know that, the nth term of an AP is; an= Sn−Sn−1. an= n(4n+1)−(n−1){4(n−1)+1} [∵ Sn= n(4n+1)] ⇒ an =4n2+n−(n−1)(4n−3) ⇒ an =4n2+n−4n2+3n+4n−3. ⇒ an =8n−3. P utn=1,⇒ … WebJul 22, 2024 · What is Sn - Sn-1 in an AP Get the answers you need, now! mindhu203 mindhu203 22.07.2024 Math Secondary School answered What is Sn - Sn-1 in an AP See answer ... 4n + 2 Subtracting s(n-1) from S(n), T(n) = 4n - 2 OR Given a is first term and d be the common difference. Sn = (n/2)[ 2a + ( n -1) d]
WebJan 27, 2024 · In an AP if Sn = n(4n + 1) then Find the AP In an AP if Sn = n(4n + 1) then Find the AP AboutPressCopyrightContact usCreatorsAdvertiseDevelopersTermsPrivacyPolicy &...
WebIn an AP, if S n=n(4n+1), fill the AP is 5, 13, __, --- Medium Solution Verified by Toppr Correct option is A 21 S n=n(4n+1) ∴S 1=a=1(4+1)=5 and S 2=a 1+a 2=2(4×2+1)=18 ⇒a+a+d=18⇒2a+d=18 ⇒d=18−2a=18−10=8 Therefore the AP is a,a+d,a+2d,.... i.e. 5,13,21,... Was this answer helpful? 0 0 Similar questions In an AP if a=1, a n=20 and S n=399, then n … bingham university post utmeWebIn the given AP, the first term is a = 7 and the common difference is d = 4. Let us assume that 301 is the n th term of AP. Then: T n = a + (n - 1)d 301 = 7 + (n - 1) 4 301 = 7 + 4n - 4 301 = 4n + 3 298 = 4n n = 74.5 But 'n' must be an integer. Hence 301 cannot be a term of the given AP. Answer: 301 cannot be a term of the given AP. bingham upholsteryWebDec 5, 2024 · Q19 In an AP if Sn = n ( 4n + 1 ) , then find the AP. If s n = 4 4n + 1, find the AP SARAL INSTITUTE 6.85K subscribers Subscribe 504 views 3 months ago CLASS 10 CBSE... bingham university admission listWebIf Sn, the sum of first n terms of an AP is given by Sn = 3n2-4n, Find the nth term? Nihar Hirani 20.9K subscribers Subscribe 29K views 2 years ago CBSE class X Arithmetic … bingham university masters programWebJun 24, 2024 · In an A.P., if Sn = n(4n + 1) then find the A.P. - YouTube 24. In an A.P., if Sn = n(4n + 1) then find the A.P.For Short Notes, Revision Notes And NCERT Solution.Visit... bingham\\u0027s winery grapevineWebLet n = 1, then a (1) = S (1) - S (0) and S (n) = (n+1)/ (n+10) that implies S (1) = 2/11,S (0) = 1/10 but S (0) = Sum of first 0 terms which is equal to zero ( S (0) = 0 ) and that is a contradiction. So the formula a (n) = S (n) -S (n-1) works only for n > 1. bingham university registration portalWebGiven that sn = 4n^2 + 2n. ----- (1) Substitute n = 1 in (1), we get sn = 4(1)^2 + 2(1) = 4 + 2 = 6. So, Sum of the first term of AP is 6 i.e a = 6. Now, Substitute n = 2 in (1), we get sn = 4(2)^2 + 2(2) = 4 * 4 + 2 * 2 = 16 + 4 = 20. So, Sum of the first 2 terms = 20. Now, First-term + second term = 20 6 + a2 = 20 a2 = 20 - 6 a2 = 4. Hence in AP, c# ziparchive create entry from stream